(3x+4)(2x^2-9x+7)=0

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Solution for (3x+4)(2x^2-9x+7)=0 equation:


Simplifying
(3x + 4)(2x2 + -9x + 7) = 0

Reorder the terms:
(4 + 3x)(2x2 + -9x + 7) = 0

Reorder the terms:
(4 + 3x)(7 + -9x + 2x2) = 0

Multiply (4 + 3x) * (7 + -9x + 2x2)
(4(7 + -9x + 2x2) + 3x * (7 + -9x + 2x2)) = 0
((7 * 4 + -9x * 4 + 2x2 * 4) + 3x * (7 + -9x + 2x2)) = 0
((28 + -36x + 8x2) + 3x * (7 + -9x + 2x2)) = 0
(28 + -36x + 8x2 + (7 * 3x + -9x * 3x + 2x2 * 3x)) = 0
(28 + -36x + 8x2 + (21x + -27x2 + 6x3)) = 0

Reorder the terms:
(28 + -36x + 21x + 8x2 + -27x2 + 6x3) = 0

Combine like terms: -36x + 21x = -15x
(28 + -15x + 8x2 + -27x2 + 6x3) = 0

Combine like terms: 8x2 + -27x2 = -19x2
(28 + -15x + -19x2 + 6x3) = 0

Solving
28 + -15x + -19x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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